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https://github.com/pjh456/OxideJS.git
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fix: 负零字面量折叠保符号不丢负号
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@@ -34,10 +34,17 @@ use crate::shared::string_pool::{pool_key_marker, pool_key_plain};
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///
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/// 一元负号只沿 `UnaryNegation` 链剥(含嵌套负号与括号),其余一元运算符
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/// (`!`/`typeof`/`void`/`~`/`+`/`delete`)终止剥壳不折。
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///
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/// 负零字面量(`-0`/`-0.0`)定值 `Number(-0.0)` 保符号:`is_int_literal(-0.0)`
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/// 为真,走 i32 臂会在 `as i32` 处丢符号。
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pub(crate) fn literal_constant(expr: &Expression) -> Option<Constant> {
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let (inner, negated) = peel_negation(expr);
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match inner {
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Expression::NumericLiteral(n) => {
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// 负零直接定值 `Number(-0.0)`,镜像运行时 `NEG` 对零的产物。
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if negated && n.value == 0.0 {
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return Some(Constant::Number(-0.0));
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}
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let value = if negated { -n.value } else { n.value };
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if is_int_literal(value) {
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Some(Constant::Int(value as i32))
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@@ -243,3 +243,35 @@ fn fold_deterministic() {
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}
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}
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}
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/// 负零字面量符号保真:折叠后常量池须含 `Number(-0.0)`(符号位置位),
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/// 不得走 i32 臂(`-0.0 as i32` 丢符号成 `Int(0)`)。符号位经 `to_bits`
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/// 比对——`Number(-0.0)` 与 `Number(0.0)` 的 `PartialEq` 相等,不能用
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/// `pool_contains` 判别。
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#[test]
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fn fold_negative_zero_sign() {
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let cases: &[(&str, OpCode)] = &[
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("-0 - 0", OpCode::SUB),
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("-0 * 1", OpCode::MUL),
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("-0 / 1", OpCode::DIV),
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("-0 % 1", OpCode::MOD),
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("(-0) ** 3", OpCode::EXP),
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];
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let neg_zero_bits = (-0.0f64).to_bits();
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for (src, op) in cases {
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let ir = emit_ir(src);
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assert_eq!(
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count_op(&ir.insts, *op),
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0,
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"{src:?} 应折叠,目标操作码 {op:?} 计数应为 0"
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);
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let has_neg_zero = ir
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.constants
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.iter()
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.any(|c| matches!(c, Constant::Number(d) if d.to_bits() == neg_zero_bits));
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assert!(
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has_neg_zero,
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"{src:?} 常量池应含折值 Number(-0.0)(符号位置位)"
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);
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}
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}
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